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Odds calculation bug

posted by navyjeff on - last edited - Viewed by 693 users
Update: Not a bug. See MattP's reply below.

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In Poker Night 2, Texas Hold 'Em, I noticed this math error and took a screen cap. No need to reply.

image

The hand is:
Player: K♠ 2♠ (93%)
Ash: 4♦ K♦ (20%)
Table: 2♥ K♣ 5♦ J♠ 10♦

Addendum:
Here's an album with more examples of the odds calc bug.
4 Comments - Linear Discussion: Classic Style
  • Here's another one, also from Poker Night 2. This time, it's Omaha, before the flop.

    Player: K♥ 7♦ A♠ J♣ (24%)
    Claptrap: A♣ 8♣ K♦ A♥ (80%)
    Table: none


    image
  • Seen this many times, but I don't think it's a bug. It's possible for there to be a draw, and in that case both players would be 100%.
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    MattP Telltale Staff
    The percentages are the likelihood that your hand can win. You may notice that if you and another character have the same hand, you'll both have the same percentage of your hand being a winning hand, even if that is 100% for both players.
  • MattP;793168 said:
    The percentages are the likelihood that your hand can win. You may notice that if you and another character have the same hand, you'll both have the same percentage of your hand being a winning hand, even if that is 100% for both players.
    I see that you are correct. Thanks for the clarification; I didn't think of that.
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